percentages Model Questions & Answers, Practice Test for ssc mts paper 1
On a test consisting of 250 questions, Jassi answered 40% of the first 125 questions correctly. What percent of the other 125 questions does she need to answer correctly for her grade on the entire exam to be 60% ?
Answer: (a)
60% of 250 = 150
40% of 125 = 50
No. of correct answers in remaining 125 questions
= 150 – 50 = 100
∴ Percentage = ${100 × 100}/125$ = 80%
Swapana spent Rs. 44,620 on Deepawali Shopping, Rs. 32,764 on buying Laptop and the remaining 32% of the total amount was left as cash with her. What was the total amount?
Answer: (a)
Total amount spent
= 44620 + 32764 = Rs. 77384
Percentage of amount spent = 100 – 32 = 68%
68% = 77384
100% = ${77384 × 100}/68$ = Rs. 113800
In an election there were two candidates X and Y, 20% of voters did not vote. 10% of the polled votes were declared invalid. X received 50% votes of polling and won by 600 votes. The total number of voters, was
Answer: (a)
40% of the students in a college play basketball, 34% of the students play tennis and the number of students who play both the games is 234. The number of students who neither play basketball nor tennis is 52%. Determine the total number of students in the college.
Answer: (b)
Let the number of students be 100.
Then number of students who play both the games
= (34 + 40) – (48) = 26
If 26 students play both the games, then the total number of students = 100
Therefore, if 234 students play both the games, then the total number of students
= $100/26 × 234$ = 900
If the numerator of certain fraction is increased by 200% and the denominator is increased by 150% the new fraction thus formed is $9/10$. What is the original fraction?
Answer: (b)
Let the numerator be x & denominator be y
$\text"x + 200 % of x"/\text"y + 150 % of y" = 9/10$
${x + 200/100 x}/{y + 150/100 y} = 9/10$
${3x}/{2.5y} - 9/10$
$x/y = {9 × 2.5}/{10 × 3} = 22.5/30 = 225/300 = 3/4$
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